X^2+19x-4200=0

Solution for X^2+19x-4200=0 equation:

X^2+19X-4200=0

a = 1; b = 19; c = -4200;
Δ = b2-4ac
Δ = 192-4·1·(-4200)
Δ = 17161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17161}=131$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-131}{2*1}=\frac{-150}{2}
=-75
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+131}{2*1}=\frac{112}{2}
=56
$